Subject: Re: [xsl] sequential numbering in xslt From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 4 Jan 2010 17:32:16 GMT |
> Also, position() does not increment is that correct? Will it not be > always 1? if you are processing a sequence of items then position() returns the number of the item in the current sequence. Ken's suggestion was that if (as is usually the case) you are starting with a sequence of documents, then position() will return the number of the current document. > I use saxon to read a directory of files, if you mean using the built in "all files in a directory" feature, then (I think) essentially you are running a separate transform on each input with no connection between them, so instead use the collection() function (perhaps with one of the saxon-specific query uri forms to refer to all the xml files in the directory) then iterate over the collection with <xsl:for-each select="collection(.......)"> this is document: <xsl:value-of select="position()"/> > failed because of the xsl:variable limitations. Declarative programming languages in which variables hold values (rather than memory locations) have the same expressive power as imperative languages, so it's misleading to call this a limitation. David
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