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Subject: Re: [xsl] another placement of nodes question From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Tue, 26 Jan 2010 15:50:06 +0100 |
Thank you for your input.The issue I am having here is when I use level2/item[last()], the processor considers both item elements under <level2> as last ones. So I still get repeated <spec> elements under both item elements.
<root> <level1> <st1> <desc><text>sample desc</text></desc> <!-- A <spec> element can occur here as well--> <level2> <item><text>r1 </text></item> <item><text>r2</text></item> </level2> <spec><para>Some spec 1</para></spec> <spec><para>Some spec 2</para></spec> </st1> </level1> </root>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output indent="yes"/> <xsl:strip-space elements="*"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template> <xsl:template match="st1/desc | st1/level2">
<xsl:apply-templates/>
</xsl:template> <xsl:template match="level1">
<step1>
<xsl:apply-templates select="st1/*"/>
</step1>
</xsl:template> <xsl:template match="level2/item">
<step2>
<xsl:apply-templates/>
</step2>
</xsl:template> <xsl:template match="level2/item[last()]" priority="3">
<step2>
<xsl:apply-templates/>
<xsl:copy-of select="../following-sibling::spec"/>
</step2>
</xsl:template><root>
<step1>
<text>sample desc</text>
<step2>
<text>r1 </text>
</step2>
<step2>
<text>r2</text>
<spec>
<para>Some spec 1</para>
</spec>
<spec>
<para>Some spec 2</para>
</spec>
</step2>
</step1>
</root>Martin Honnen http://msmvps.com/blogs/martin_honnen/
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