Subject: Re: [xsl] another placement of nodes question From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Tue, 26 Jan 2010 15:50:06 +0100 |
Thank you for your input.The issue I am having here is when I use level2/item[last()], the processor considers both item elements under <level2> as last ones. So I still get repeated <spec> elements under both item elements.
<root> <level1> <st1> <desc><text>sample desc</text></desc> <!-- A <spec> element can occur here as well--> <level2> <item><text>r1 </text></item> <item><text>r2</text></item> </level2> <spec><para>Some spec 1</para></spec> <spec><para>Some spec 2</para></spec> </st1> </level1> </root>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output indent="yes"/> <xsl:strip-space elements="*"/>
<xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template>
<xsl:template match="st1/desc | st1/level2"> <xsl:apply-templates/> </xsl:template>
<xsl:template match="level1"> <step1> <xsl:apply-templates select="st1/*"/> </step1> </xsl:template>
<xsl:template match="level2/item"> <step2> <xsl:apply-templates/> </step2> </xsl:template>
<xsl:template match="level2/item[last()]" priority="3"> <step2> <xsl:apply-templates/> <xsl:copy-of select="../following-sibling::spec"/> </step2> </xsl:template>
<root> <step1> <text>sample desc</text> <step2> <text>r1 </text> </step2> <step2> <text>r2</text> <spec> <para>Some spec 1</para> </spec> <spec> <para>Some spec 2</para> </spec> </step2> </step1> </root>
Martin Honnen http://msmvps.com/blogs/martin_honnen/
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