Subject: RE: [xsl] XML attribute value to pattern match of the replace function From: "Selvaganesh" <selvaganesh_t@xxxxxxxxxxxxxx> Date: Mon, 22 Feb 2010 17:36:11 +0530 |
Thanks Martin. -----Original Message----- From: Martin Honnen [mailto:Martin.Honnen@xxxxxx] Sent: Monday, February 22, 2010 4:54 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] XML attribute value to pattern match of the replace function Selvaganesh wrote: > >> You need to concat the attribute values e.g. >> select="replace(., concat('(', @party1, '.*?', @party2, ')'), >> '<cite>$1</cite>')" > > In case the xml content appear parenthesis () does not process the replace > function can u suggest any other way. > > Also I have tried below way, but does not working. > > select="(concat('(', string(@party1), '.*?', string(@party2), ')'), > '<cite>$1</cite>')"/> > > > Also I have tried the analyze-string method but it was working fine but > above issue was repeated. Use the function defined here http://www.xsltfunctions.com/xsl/functx_escape-for-regex.html to escape the attribute values e.g. <xsl:element name="caseref"> <xsl:analyze-string select="." regex="({functx:escape-for-regex(@party1)}.*?{functx:escape-for-regex(@party 2)})"> <xsl:matching-substring> <xsl:element name="casetitle"> <xsl:value-of select="regex-group(1)"/> </xsl:element> </xsl:matching-substring> <xsl:non-matching-substring> <xsl:value-of select="."/> </xsl:non-matching-substring> </xsl:analyze-string> </xsl:element> </xsl:template> -- Martin Honnen http://msmvps.com/blogs/martin_honnen/ Confidentiality Notice: This transmittal is a confidential communication. If you are not the intended recipient, you are hereby notified that you have received this transmittal in error and that any review, dissemination, distribution or copying of this transmittal is strictly prohibited. If you have received this communication in error, please notify this office immediately by reply and immediately delete this message and all of its attachments, if any.
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