Re: [xsl] Order of items in current-group()

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

>> Hope that in the next spec they will not use latin words that
>> would require 5 years medical education to understand.
>
> I never had a medical education, though I did learn some Latin in school
and
> in church. It's good training for anyone who wants to be a programmer. But
> looking at the text of the spec here, I don't see any difficult words. I'm
> actually quite pleased with the term "order of first appearance" as a way
of
> conveying the ordering of groups intuitively, though the formal definition
> of what it means proved tricky.


What I find not justified is the use of the word "population". I also
provided an example of simpler and more understandable wording:

"The order of items in the current-group() is the same as their order
in the sequence, specified in the @select attribute of
<xsl:for-each-group>."



--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
Never fight an inanimate object
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play




On Wed, Feb 24, 2010 at 12:06 PM, Michael Kay <mike@xxxxxxxxxxxx> wrote:
>> Hope that in the next spec they will not use latin words that
>> would require 5 years medical education to understand.
>
> I never had a medical education, though I did learn some Latin in school
and
> in church. It's good training for anyone who wants to be a programmer. But
> looking at the text of the spec here, I don't see any difficult words. I'm
> actually quite pleased with the term "order of first appearance" as a way
of
> conveying the ordering of groups intuitively, though the formal definition
> of what it means proved tricky.
>
> In fact Vladimir's question (about the order of items within a group) is
not
> as well answered in the spec as I would like. For each of the four grouping
> methods a procedural algorithm is given, and the order of items in a group
> depends on you understanding that when items are "added to a group", they
> are added at the end.
>
> It perhaps ought to say somewhere that items within each group will always
> be in population order (because they are), but I don't think it actually
> says that. Though perhaps that's because it's not a meaningful thing to
> assert in the case where the items in the population don't have distinct
> identity (e.g. when one node appears more than once in the input sequence,
> in different positions).
>
> Regards,
>
> Michael Kay
> http://www.saxonica.com/
> http://twitter.com/michaelhkay
>
>
>>
>>
>> --
>> Cheers,
>> Dimitre Novatchev
>> ---------------------------------------
>> Truly great madness cannot be achieved without significant
>> intelligence.
>> ---------------------------------------
>> To invent, you need a good imagination and a pile of junk
>> -------------------------------------
>> Never fight an inanimate object
>> -------------------------------------
>> You've achieved success in your field when you don't know
>> whether what you're doing is work or play
>>
>>
>>
>>
>> On Wed, Feb 24, 2010 at 11:02 AM, Martin Honnen
>> <Martin.Honnen@xxxxxx> wrote:
>> >
>> > Vladimir Nesterovsky wrote:
>> >
>> >> Whether the xslt 2.0 spec defines the order of items in
>> sequence returned from current-group() function?
>> >
>> > The select attribute of xsl:for-each-group selects a
>> sequence of items, called the population. The order of items
>> in that sequence is called the population order. When forming
>> the groups, the items in the population are examined in
>> population order and then, if they belong to a group, added
>> to a group. So that way the order of items in the population
>> determines the order of items in a group.
>> >
>> > --
>> >
>> > B  B  B  B Martin Honnen
>> > B  B  B  B http://msmvps.com/blogs/martin_honnen/