Re: [xsl] Re: Display the number of records in a group

[David Carlisle <davidc@xxxxxxxxx>]

On 17/03/2010 16:15, anil kumar wrote:

I'm not sure what the problem was any more, but inide the for-each-group 
position() goes from 1 to 8, as last() is 8 as there are 8 groups.

If you don't want the groups, just the number, you can stop after the 
first and output 8, eg:


<xsl:for-each-group select="G_ROW[INTRA_EU_TRX_CODE =
('GOOD','TRIANGULATION')]"
group-by="concat(VAT_TAX_NO,BILL_CUST_NAME,INTRA_EU_TRX_CODE)">
<xsl:if test="position()=1">[<xsl:value-of select="last()"/>]</xsl:if>
</xsl:for-each-group>

David

 saxon9 ak.xml ak.xsl
<?xml version="1.0" encoding="UTF-8"?>
<mezo eazon="0A0001D003A">[8]</mezo>

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