Re: [xsl] sorting strings (not default sorting) with xslt

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2010-03-18 13:12 +0100, Robby Pelssers wrote:
> I would like to sort following strings ['BSS84/A2', 'BSS84/DG', 'BSS84'],
>
> default sorting results in:
>
> BSS84/A2 -> BSS84/DG -> BSS84

Not with the processor I am using (Saxon).

> But the customer wants them sorted like
>
> BSS84 -> BSS84/A2 -> BSS84/DG

So would I!

> What's the easiest way to accomplish this?
> Do I need to write a custom comparator function or can I use some 
> <xsl:sort> shortcuts or is the only way to use collations?

Which processor are you using?

Below is an example ... what you want is ASCIIbetical and so the 
default sort collation of Unicode is fine.

I hope this helps.

. . . . . . . . . . . Ken

t:\ftemp>type robby.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="2.0">

<xsl:output method="text"/>

<xsl:template match="/">
  <xsl:for-each select="('BSS84/A2', 'BSS84/DG', 'BSS84')">
    <xsl:sort/>
    <xsl:value-of select="."/>
    <xsl:text>
</xsl:text>
  </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

t:\ftemp>xslt2 robby.xsl robby.xsl
BSS84
BSS84/A2
BSS84/DG

t:\ftemp>

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