Subject: Re: [xsl] XPath discovery tool? From: Wolfgang Laun <wolfgang.laun@xxxxxxxxx> Date: Sun, 25 Apr 2010 16:20:54 +0200 |
Perhaps a stylesheet determining the XPath expressions for all elements and adding them as comments in front of each XML element? -W <?xml version="1.0"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:str="http://my/str"> <xsl:function name="str:path" as="xsd:string"> <xsl:param name="node" as="node()?"/> <xsl:for-each select="$node"> <xsl:choose> <xsl:when test="parent::node()"> <xsl:value-of select="concat(str:path(parent::node()), '/', node-name($node))"/> </xsl:when> <xsl:otherwise> <xsl:value-of select="''"/> </xsl:otherwise> </xsl:choose> </xsl:for-each> </xsl:function> <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> <xsl:template match="*"> <xsl:comment><xsl:value-of select="str:path(.)"/> </xsl:comment> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="@*"> <xsl:copy/> </xsl:template> </xsl:stylesheet> On Sun, Apr 25, 2010 at 2:09 AM, <cknell@xxxxxxxxxx> wrote: > I have a number of XML-formatted Excel workbooks from which I wish to extract data. While the procedure for determining the XPath to any particular cell's value is not difficult, it is tedious. Does anyone know of a tool into which I could load the XML file, select an element, and automatically display the XPath to that element? > > -- > Charles Knell > cknell@xxxxxxxxxx - email
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