Re: [xsl] Determine position in node sequence based on criteria

[Michael Kay <mike@xxxxxxxxxxxx>]

In xquery you do
> for $i at $pos in ../s return
>   if (...) then $pos else ()
>
> However thats exactly the same as:
>
> for $i in ../s return
>   if (...) then 1 + count($i/preceding-sibling::s) else ()
>
>    

It's the same in this case, but

(a) it relies on the "in" expression ../s returning a sequence of 
siblings, and

(b) the second solution is likely to be O(n^2) while the first is likely 
to be O(n).

Michael Kay
Saxonica