RE: [xsl] Selecting lots of nodes with lots of criteria

["Fabien Tillier" <f.tillier@xxxxxxxx>]

Thanks (again) Martin !
select="//Row[NUMERO = (1, 2, 3, 4, 5, 6, 7, 8)]"
is working !!!! (and a lot more faster...)
You guessed right for XSLT 2.0, of course...

Best regards,
Fabien



-----Message d'origine-----
De : Martin Honnen [mailto:Martin.Honnen@xxxxxx]
Envoyi : jeudi 2 septembre 2010 17:19
@ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Objet : Re: [xsl] Selecting lots of nodes with lots of criteria

Fabien Tillier wrote:
> Hi List.
> I think I have reached some limitations of the XSL parser.
> I am trying to select a list of nodes from a document based on criteria
> like
> <xsl:call-template name="tab208">
> <xsl:with-param name="rows"
>
> select="//Row[NUMERO=1]|//Row[NUMERO=2]|//Row[NUMERO=3]|//Row[NUMERO=4]|
> //Row[NUMERO=5]|//Row[NUMERO=6]|//Row[NUMERO=7]|//Row[NUMERO=8]"/>
> </xsl:with-param>
> </xsl:call-template>

Test whether
   select="//Row[NUMERO = 1 or NUMERO = 2 or NUMERO = 3 (and so on)]"
performs better.
Or, as you mention Kernow meaning you use XSLT 2.0, you could try
   select="//Row[NUMERO = (1, 2, 3, 4, 5, 6, 7, 8)]"



--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/