Re: [xsl] Reranging Numbers

[Michael Kay <mike@xxxxxxxxxxxx>]

 First parse the string and convert to a sequence of integers, 
something like:

<xsl:for-each select="tokenize(., ',\s+')">
<xsl:choose>
<xsl:when test="contains(., '-')">
<xsl:sequence select="xs:integer(substring-before(., '-') to 
xs:integer(substring-after(., '-')"/>
</
<xsl:otherwise>
<xsl:sequence select="xs:integer(.)"/>
</
</
</

Then do grouping using a method first suggested by David Carlisle on 
this list:

<xsl:for-each-group select="..." group-adjacent=". - position()">
<xsl:choose>
<xsl:when test="count(current-group()) gt 1">
<xsl:value-of select="current-group()[1], current-group()[last()]" 
separator="-"/>
</
<xsl:otherwise>
<xsl:value-of select="current-group()[1]"/>
</
</
</

On 21/09/2010 8:09 AM, Jeff Sese wrote:
> Hi,
>
> If i have a node like:
>
> <node>1, 2, 3, 5-8, 9, 11, 15</node>
>
> How can I make it as:
>
> <node>1-3, 5-9, 11, 15</node>
>
> I'm using XSLT 2.0
>
> Thanks,
> -- Jeff