Subject: Re: [xsl] Making nested elements from elements with level attributes From: russurquhart1@xxxxxxxxxxx Date: Thu, 23 Sep 2010 16:53:38 -0500 (CDT) |
Thank you! I have modified your suggestions to sort of work. The code is below. I need to carry to the result tree, the siblings that fall in the current section. I know i need something along the lines of following-sibling: up to next section. Or is there another way to get those in this algorithm. The current line only get all siblings but the headings. Any suggestions? Thank you so much! Russ <?xml version='1.0'?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version='2.0' xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:template name="process-level"> <xsl:param name="population" required="yes" as="element()*"/> <xsl:param name="level" required="yes" as="xs:integer"/> <xsl:for-each-group select="$population" group-starting-with="section[xs:integer(@level) eq $level]"> <xsl:element name="Subsection"> <xsl:value-of select="@level"/> <!-- I know this line needs to be changed to get the siblings up to the next section element. --> <xsl:copy-of select="following-sibling::*[name()!='section']"/> <xsl:call-template name="process-level"> <xsl:with-param name="population" select="current-group()[position() != 1]"/> <xsl:with-param name="level" select="$level + 1"/> </xsl:call-template> </xsl:element> </xsl:for-each-group> </xsl:template> <xsl:template match="article"> <xsl:call-template name="process-level"> <xsl:with-param name="population" select="./section"/> <xsl:with-param name="level" select="2"/> </xsl:call-template> </xsl:template> </xsl:stylesheet> >The elegant algorithm IS a recursive routine with a named template: see >http://www.saxonica.com/papers/ideadb-1.1/mhk-paper.xml >for a solution of a similar problem (Stage Two is the relevant part) >Michael Kay >Saxonica
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