[xsl] Sorting using more than value

[Susan Bodnik <aquasue@xxxxxxxxx>]

I am having problems in sorting using one of two possible values.I have a
template that creates an index using the indexterm element. 

Here is a
snippet of XML:

<p>Here is an <indexterm>index entry</indexterm> without an
attribute, and the 
contents of the element will display in the index. This
<indexterm 
term.entry="Alternate text">index entry</indexterm> does have an
attribute, and 
the contents of the attribute will display in the index rather
than the content 
of the indexterm element. </p>

I need to be able to sort
the index using one of two possible values. If the 
indexterm doesn't contain
a term.entry attribute, it should sort using the 
content of the indexterm
element. If the indexterm element contains a term.entry 
attribute, then it
should sort using the value of the term.entry attribute.
I have the following
that sorts the index. The template outputs the value of the 
term.entry
attribute if present, but it sorts only using the content of the 
indexterm
element:

   <xsl:for-each-group select="//indexterm"  group-by="."> 
   
<xsl:sort
select="translate(text(),'abcdefghijklmnopqrstuvwxyz','ABCDEFGHIJKLMNOPQRSTUV
WXYZ')"/>

  
    <div class="index">  
    <xsl:choose>
    <xsl:when
test="@term.entry"><span><xsl:value-of 
select="@term.entry"/><xsl:text> -
</xsl:text></span></xsl:when> 

    <xsl:otherwise><span><xsl:value-of
select="."/><xsl:text> - 
</xsl:text></span></xsl:otherwise>
       
 </xsl:choose>    
        </div> 
</xsl:for-each-group>

How would I be able
to sort the index entries using the content of the indexterm 
element (when
there is no term.entry element) or the term.entry attribute for 
the indexterm
element (if present)?

Thanks for any assistance with this.
Susan