Subject: Re: [xsl] XSL comparing nodesets by name only From: Piet van Oostrum <piet@xxxxxxxxxxxxxx> Date: Mon, 15 Nov 2010 08:24:34 -0400 |
Markus Ohlenroth wrote: > I use XSLT 1.0 > > Given the following nodesets: > > <data:me1> <a></a> <b/> </data:me1> > > <data:me2> <a>value</a> <dd></dd> </data:me2> > > > <xsl:variable name="me1" select="//data:me1/*"/> <xsl:variable > name="me2" select="//data:me2/*"/> > > I want to find out if the two nodesets share one or more elements. I > only want a comparison regarding their nodenames not the values of > the nodes. In the above example $me1 and $me2 share the name of one > element: and that is the element "<a/>". So my nodeset comparison > should return "true". In XSLT 1.0: <xsl:value-of select="name($me1) = name($me2)"/> In 2.0: <xsl:value-of select="$me1/name() = $me2/name()"/> -- Piet van Oostrum Cochabamba. URL: http://pietvanoostrum.com/ Nu Fair Trade woonartikelen op http://www.zylja.com
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] XSL comparing nodesets by nam, Markus Ohlenroth | Thread | Re: [xsl] XSL comparing nodesets by, Martin Honnen |
[xsl] XSL comparing nodesets by nam, Markus Ohlenroth | Date | Re: [xsl] XSL comparing nodesets by, Martin Honnen |
Month |