Re: [xsl] Iteration of for() for first 100 intergers.

[Michael Kay <mike@xxxxxxxxxxxx>]

On 18/11/2010 16:09, ram wrote:
> Hi,
>     I am looking for simple for() which will iterate through first 100 numbers.   how can i do that.
>
> for(int i=0;i<=100;i++){
>     System.out.println("each value"+i);
> }
In XPath 2.0:

for $i in 1 to 100 return .....

In XPath 1.0

you're out of luck. There's a workaround to iterate over a node-set 
containing n nodes, and use position().

Michael Kay
Saxonica