Subject: Re: [xsl] Selecting the node which have child without repition From: Mukul Gandhi <gandhi.mukul@xxxxxxxxx> Date: Fri, 19 Nov 2010 09:29:34 +0530 |
The following XPath expression seem to work: //b[c][not(@name = following::b[c]/@name)] On Thu, Nov 18, 2010 at 11:05 PM, Rashi Bhardwaj <rashi.bhardwaj@xxxxxxxxx> wrote: > Hi all, > > I am facing a problem while selecting a node through xpath....please help me out > > Here is the input xml > > <test> > B <a> > B B <b name ='1'></b> > B B <b name ='2'></b> > B B <b name ='3'> > B B B B <c></c> > B B </b> > B B <b name ='4'> > B B B B <c></c> > B B B B <c></c> > B B </b> > B </a> > B <a> > B <b name ='1'></b> > B <b name ='2'> > B B B <c></c> > B </b> > B <b name ='3'></b> > B <b name ='4'> > B B <c></c> > B </b> > B </a> > </test> > > Xpath: > //b[child::c][not(./@name=following-sibling::b/@name)] > > Output: > b name="3" > b name="4" > b name="2" > b name="4" > > What I want is to select all 'b' that have child 'c', provide the 'b' > with same '@name' which are selected first should not be selected > further. > > Desired output: > > Output: > b name="3" > b name="4" > b name="2" > > As b with @name = 4 has already been searched, it should not come > again in search. > > Please help me .....thanks a lott.... > > Rashi -- Regards, Mukul Gandhi
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