[xsl] Finding the position of an element wrt to other elemen

Hi,

I want the position of an element (there is a condition for selecting
that element) relative to other element

Input XML:
<test>
<a>
<b name ='1'></b>
<b name ='2'></b>
<b name ='3'>
<c></c>
</b>
<b name ='4'>
	<c></c>
	<c></c>
</b>
<b name ='4'>
	<c></c>
	<c></c>
</b>
</a>
<a>
<b name ='1'></b>
<b name ='2'>
<c></c>
</b>
<b name ='3'></b>
<b name ='4'>
	<c></c>
</b>
</a>
</test>

XSL I using:

<xsl:template match="/">
		<html>
			<body>
			<table>
				<tbody>
					<tr>
						<th>
						<xsl:value-of select="$CustomSelect"/>
						</th>
					</tr>
				</tbody>
			</table>
			</body>
		</html>
	</xsl:template>
	<xsl:variable name="CustomSelect">
			<xsl:text>position: </xsl:text>
				<xsl:call-template name="test">
				</xsl:call-template>
		</xsl:variable>
		<xsl:template name="test">
  <xsl:call-template name="test2">
  <xsl:with-param name="node" select="//b[c][not(@name
=preceding::b[child::c]/@name)]/@name"/>
    </xsl:call-template>
     </xsl:template>
<xsl:template name="test2">
<xsl:param name="node"/>
<xsl:for-each select="$node">
<xsl:value-of select="position()"/>
<xsl:if test="position()!=last()"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

Output I m getting is position 123, but i want it should count all b
from top to end at any level and give relative position like here it
should give 342. I m getting how to go ahead...please help  me out
thanks......





Rashi Bhardwaj

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[xsl] Finding the position of an element wrt to other element