Re: [xsl] Need to process mixed content(text() and node()) in string matching

Subject: Re: [xsl] Need to process mixed content(text() and node()) in string matching
From: "Imsieke, Gerrit, le-tex" <gerrit.imsieke@xxxxxxxxx>
Date: Thu, 09 Dec 2010 10:08:41 +0100
With XSLT 2.0, you could first replace ':' with some empty element and then, in a second pass, group all node()s in the paragraph, starting each group with that newly introduced empty element.

On 09.12.2010 10:02, Mandar Jagtap wrote:
Hi,

I have following scenario:

Source xml is:

<p>This is paragraph text..<b>and bold</b>  and normal<i>and
italic</i>  with value: ParagraphValue.</p>

The XSLT should match the string (mixed with text() of<p>, content of
element<i>,<b>) as " This is paragraph text..and bold and normal and
italic with value" in<p>  element and desired output given below.

<paragraph1>This is paragraph text..<b>and bold</b>  and normal<i>and
italic</i>  with value</paragraph1>
<paragraph2>ParagraphValue.</paragraph2>

I tried with following approach:

<xsl:template match="p">
   <xsl:choose>
     <xsl:when test="contains(. , ':')">
       <paragraph1><xsl:value-of select="substring-before(., ':')"/></paragraph1>
       <paragraph2><xsl:value-of select="substring-after(., ':')"/></paragraph2>
     </xsl:when>
    <xsl:otherwise><paragraph1><xsl:avlue-of
select="."/></paragraph1></xsl:otherwise>
   </xsl:choose>
</xsl:template>

But with I could get only string but not elements<b>  and<i>
alongwith its content.

Any suggestions on what would be best approach to achieve this?

Thanks in advance...


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