Re: [xsl] How to insert a set nodes under the root of an arbitrary XML using XSL?

[Graydon <graydon@xxxxxxxxx>]

On Fri, Jan 07, 2011 at 04:07:43PM -0500, William C Thompson scripsit:
> I would love to know how to (using XSL) insert a pre-determined node a
> (with children b and c) as a child of the root node of an arbitrary XML.  I
> know how to apply the XSL once I've got it.  I just need help with the XSL.
> All the examples I'm finding online assume a pre-determined XML, which I
> cannot in this case.
[snip illustrative abstract example]
> Most importantly, please note that any solutions with hard-coded references
> to any node names (other than those I want to insert) are not usable for
> me.  I have no control over the schema of the XML into which I'm sticking
> these other nodes.  I know only that it's a valid XML file and the root has
> at least one child.  The above example is a purely made up example designed
> to illustrate the question.

You can do this with two templates, at least if I understand the question:

<!-- Our old friend the identity transform -->
<xsl:template match="node()|@*">
    <xsl:copy>
        <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
</xsl:template>

<!-- match the first element child of the root node -->
<xsl:template match="/*[1]">
    <element> Your fixed content goes here as literal result elements </element>
    <!-- but don't lose the former first element child of the root node -->
    <xsl:copy>
        <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
</xsl:template>

-- Graydon