Re: [xsl] Aligning Parallel Columns

[Jeroen Hellingman <jeroen@xxxxxxxx>]

On 2011-01-15 13:38, G. Ken Holman wrote:
> At 2011-01-15 07:22 -0500, I wrote:
>> Use for-each-group on the name attributes.  You will end up with five
>> groups.  As you walk through each of the five groups, looking at each
>> element's parent will tell you which side of the table the item
>> belongs in.
> 
> More precisely, as you walk through each of the five groups of
> attributes, walk through the parent elements in table column order to
> select that member of the group that is a descendant of the parent. 
> That way you'll walk through the group in the correct order to generate
> table cells and know if the item is absent from the parent to know to
> put in an empty cell.
> 
> I hope this helps.
> 
> . . . . . . . . Ken

Thanks for the hint. My current solution depends on being able to sort
the names, which isn't entirely satisfying ($a and $b contain the two
divs to be aligned):

    <table>
        <xsl:for-each-group group-by="@name" select="$a/p, $b/p">
            <xsl:sort select="@name"/>

            <xsl:variable name="name" select="@name"/>

            <tr>
                <td>
                    <xsl:value-of select="$name"/>
                </td>
                <td>
                    <xsl:if test="$a/p[@name = $name]">
                        <xsl:apply-templates select="$a/p[@name = $name]"/>
                    </xsl:if>
                </td>
                <td>
                    <xsl:if test="$b/p[@name = $name]">
                        <xsl:apply-templates select="$b/p[@name = $name]"/>
                    </xsl:if>
                </td>
             </tr>
        </xsl:for-each-group>
    </table>


Jeroen.