Re: [xsl] Param value not getting value passed

[David Carlisle <davidc@xxxxxxxxx>]

On 30/01/2011 22:05, Karl Stubsjoen wrote:
> I'm perplexed.  I have a template match routine and param value that
> is not receiving the param value passed.  I am passing the param value
> like this:
>
> <xsl:with-param name="group-value" select="number(16)"/>

you could miss out the number()   (16 s already a number)


> The param is defined in the template match like this:
> <xsl:param name="group-value">0</xsl:param>

better to use select="0" (but that is not the cause of the problem)
> The value is always:
> type:ABC
> value: "0"
> (According to Oxygen)

so the working assumption must be that the parameter is not being passed 
down, typically this is caused by having

<foo>
    <a>
       <b>


and the template matching foo saying

<xsl:apply-templates>
   <xsl:with-param name="x" select="16"/>
</

and the template for b having
<xsl:param name="x"/>

the solution is to make a pass on teh param with

<xsl:with-param name="x" select="$x"/>

or (in xslt 2) declaring the parameter to be tunnel="yes" when this 
passing through intermediate templates is automatic.

David