Re: [xsl] Thought i knew this but i guess not

[Abel Braaksma <abel.online@xxxxxxxxx>]

No need for an xsl:if there. also, your second template copies the 
current node to the result tree as well, from your question, I think you 
don't want this. Here's a way to do it (not tested):

<!-- capture filter1 and filter10 -->
<xsl:template match="*[@filter = 'filter1' or @filter = 'filter10']">
<xsl:copy-of select="." />
</xsl:template>

<!-- ignore the rest -->
<xsl:template match="* | @*">
<xsl:apply-templates />
</xsl:template>


Kind regards,
Abel


On 22-2-2011 20:19, russurquhart1@xxxxxxxxxxx wrote:
> I am trying to extract only elements having a filter attribute value of 'filter10', 'filter1' or has no filter attributes at all. I would have thought this would do it:
>
> But other filter values are making it into the result file.
>
>
> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>    <xsl:template match="*[@filter]">
>      <xsl:if test="contains(@filter, 'filter10') or contains(@filter, 'filter1')">
>
>        <xsl:copy-of select="." />
>      </xsl:if>
>    </xsl:template>
>    <xsl:template match="*[not(@filter)]">
>      <xsl:copy-of select="." />
>    </xsl:template>
> </xsl:stylesheet>
>
>
> Can someone provide some help on this!
>
> Thanks so much!
>
>
> Russ