Subject: Re: [xsl] HST's answers Re: [xsl] Efficient way to check sequence membership - From: Michael Kay <mike@xxxxxxxxxxxx> Date: Thu, 03 Mar 2011 10:50:19 +0000 |
It seems the following expression can do checks based on node identity (I inferred this meaning from Dave's requirement... the "member()" function),
some $x in $seq satisfies ($x is $item)
Michael Kay Saxonica
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