Subject: Re: [xsl] block selection question (XSLT 1.0) From: Andrew Welch <andrew.j.welch@xxxxxxxxx> Date: Fri, 6 May 2011 10:55:13 +0100 |
On 6 May 2011 10:13, Hermann Stamm-Wilbrandt <STAMMW@xxxxxxxxxx> wrote: > Hello, > > I know that this is basic but I cannot get it done correctly. > > Input: > <lines> > <line></line> > <line>A1</line> > <line>1</line> > <line>B1</line> > <line></line> > <line>A2</line> > <line>2</line> > <line>2</line> > <line>2</line> > <line>B2</line> > <line></line> > <line></line> > </lines> > > Intended output (blockwise, start at A, all including next B): > <line>A1</line> > <line>1</line> > > <line>A2</line> > <line>2</line> > <line>2</line> > <line>2</line> A group-starting-with solution: <xsl:variable name="a-to-z" select="('a', 'b')"/> <xsl:template match="/"> <lines> <xsl:for-each-group select="$input/lines/line[normalize-space(.)]" group-starting-with="line[lower-case(substring(., 1, 1)) = $a-to-z]"> <xsl:if test="current-group()[2]"> <group> <xsl:copy-of select="current-group()"/> </group> </xsl:if> </xsl:for-each-group> </lines> </xsl:template> ...should be enough to start with. -- Andrew Welch http://andrewjwelch.com
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