Re: [xsl] block selection question (XSLT 1.0)

[Andrew Welch <andrew.j.welch@xxxxxxxxx>]

On 6 May 2011 10:13, Hermann Stamm-Wilbrandt <STAMMW@xxxxxxxxxx> wrote:
> Hello,
>
> I know that this is basic but I cannot get it done correctly.
>
> Input:
> <lines>
>  <line></line>
>  <line>A1</line>
>  <line>1</line>
>  <line>B1</line>
>  <line></line>
>  <line>A2</line>
>  <line>2</line>
>  <line>2</line>
>  <line>2</line>
>  <line>B2</line>
>  <line></line>
>  <line></line>
> </lines>
>
> Intended output (blockwise, start at A, all including next B):
> <line>A1</line>
> <line>1</line>
>
> <line>A2</line>
> <line>2</line>
> <line>2</line>
> <line>2</line>

A group-starting-with solution:

<xsl:variable name="a-to-z" select="('a', 'b')"/>

<xsl:template match="/">
  <lines>
    <xsl:for-each-group select="$input/lines/line[normalize-space(.)]"
group-starting-with="line[lower-case(substring(., 1, 1)) = $a-to-z]">
      <xsl:if test="current-group()[2]">
        <group>
          <xsl:copy-of select="current-group()"/>
        </group>
      </xsl:if>
    </xsl:for-each-group>
  </lines>
</xsl:template>

...should be enough to start with.


--
Andrew Welch
http://andrewjwelch.com