Re: [xsl] Simple xpath expression---child node of variable---stumping me

[George Cristian Bina <george@xxxxxxxxxxxxx>]

Hi Steve,

If you did not set the XPath default namespace then any name test 
without a prefix will select elements from no namespace. You need either 
a prefix mapped to the http://dita4publishers.org/enumerables namespace 
and then use that to qualify the title name test or declare the XPath 
default namespace to pint to the http://dita4publishers.org/enumerables 
namespace, see an example below:

<xsl:value-of select="$enumFig/title"
xpath-default-namespace="http://dita4publishers.org/enumerables"; />

Note that the XPath default namespace is inheritable, similar with the 
namespace declarations, if you declare it on an element, it applies on 
the whole tree rooted on that element, unless of course it is not 
redefined on some inner element.

Best Regards,
George
--
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com

On 5/11/11 9:58 AM, Steve Fogel wrote:
> Hi, all...
>
> This seems like a no-brainer, but it's not producing the desired results.
>
> If $enumFig is declared as:
>
> <xsl:variable name="enumFig" as="element()+" select="$enumerables//*[@sourceId=$figId]" />
>
> and in my debugging<xsl:message>  output, $enumfig is:
>
> <fig xmlns="http://dita4publishers.org/enumerables";
>        sourceId="topicidfig-38-24-22"
>        id="UNAMECommandOutput-FF8FD85A"
>        class="- topic/fig "><title>UNAME Command Output</title></fig>
>
> and<xsl:sequence select="$enumFig/*" />   returns this:
>
> <title xmlns="http://dita4publishers.org/enumerables";>UNAME Command Output</title>
>
> then why does the following return an empty sequence?
>
> <xsl:value-of select="$enumFig/title" />
>
> I'm stumped!!
>
> Thx
>
> Steve