Subject: Re: [xsl] need xsl template for this xml and html From: Matthieu Ricaud-Dussarget <matthieu.ricaud@xxxxxxxxx> Date: Wed, 25 May 2011 21:04:45 +0200 |
<xsl:template match="item"> <li><xsl:apply-templates/></li> </xsl:template> <xsl:template match="ref"> <a href="country.aspx?id={@id}"><xsl:apply-templates/></a> </xsl:template> <xsl:template match="ref/b"> <xsl:apply-templates/> </xsl:template>
Hope this helps, Regards, Matt.
Hi,
I'm new to XSL. Currently I'm using XSLT 1.0 parsing tools.
I'm integrating content from a 3rd party, where part of the XML looks like this (i've modified the content from the original):
<item> <ref id="ireland"> <b>Republic of Ireland</b> </ref>: is a country with a population of 5 million ... </item>
The resultant HTML that I WANT will look something like this:
<li><a href="country.aspx?id=ireland">Republic of Ireland</a>: is a country with a population of 5 million ...</li>
However, no matter what I try, the closest I can come up with is this:
<li><a href="country.aspx?id=ireland">Republic of Ireland</a>: Republic of Ireland is a country with a population of 5 million ...</li>
(notice the double "Republic of Ireland" in there). The question is how do I prevent the text inside the<ref> tags been repeated, but yet get the value of the rest of the text outside the<ref> tags ...
These are the templates that I am using and / or have tried:
<xsl:template match="item"><li><xsl:apply-templates select="ref" mode="include" /><xsl:value-of select="."/></li></xsl:template> <xsl:template match="*/ref" mode="include"> <a href="country.aspx?id={@id}"><xsl:value-of select="."/></a> </xsl:template> <xsl:template match="*/ref" mode="exclude"></xsl:template> <xsl:template match="*/ref"></xsl:template>
Hope this makes sense and thank you in advance,
Frank
-- Matthieu Ricaud IGS-CP Service Livre numirique
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