Re: [xsl] Java list extension

[Michel Hendriksen <michel.hendriksen@xxxxx>]

probeer select=*.xml

On Tue, Jul 5, 2011 at 2:14 PM, Michel Hendriksen
<michel.hendriksen@xxxxx> wrote:
>
> probeer select=*.xml
>
> On Tue, Jul 5, 2011 at 2:09 PM, Hermann Stamm-Wilbrandt <STAMMW@xxxxxxxxxx>
wrote:
>>
>> Andew,
>>
>> > You can get a list of all the files in the directory and
>> > subdirectories by doing:
>>
>> > <xsl:for-each
>>
select="collection('file:///path/to/dir/?select=*;recurse=yes;on-error=ignore
')">
>> >   <xsl:value-of select="document-uri(.)"/>
>>
>> how can you get the names of non-XML files?
>> Saxon reports errors for applying document-uri() to Non-XML files.
>>
>> [stammw@br8ggx73 xslt20]$ ll
>> total 12
>> -rw-rw-r-- 1 stammw stammw 403 Jul  5 14:04 ls.xsl
>> -rw-rw-r-- 1 stammw stammw   5 Jul  5 14:03 some.xml
>> -rw-rw-r-- 1 stammw stammw   4 Jul  5 14:04 tst.txt
>> [stammw@br8ggx73 xslt20]$
>> [stammw@br8ggx73 xslt20]$ saxon ls.xsl some.xml
>> Error on line 1 column 1 of tst.txt:
>>  SXXP0003: Error reported by XML parser: Content is not allowed in
>> prolog.
>> file:/home/stammw/xslt/xslt20/ls.xsl
>> file:/home/stammw/xslt/xslt20/some.xml
>> [stammw@br8ggx73 xslt20]$
>> [stammw@br8ggx73 xslt20]$ cat ls.xsl
>> <xsl:stylesheet version="2.0"
>>  xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>> >
>>  <xsl:output omit-xml-declaration="yes" />
>>
>>  <xsl:template match="/">
>>    <xsl:for-each
>>
select="collection('file:///home/stammw/xslt/xslt20/?select=*;recurse=yes;on-
error=ignore')">
>>      <xsl:value-of select="document-uri(.)"/><xsl:text>&#10;</xsl:text>
>>    </xsl:for-each>
>>  </xsl:template>
>>
>> </xsl:stylesheet>
>> [stammw@br8ggx73 xslt20]$
>>
>>
>> Mit besten Gruessen / Best wishes,
>>
>> Hermann Stamm-Wilbrandt
>> Developer, XML Compiler, L3
>> Fixpack team lead
>> WebSphere DataPower SOA Appliances
>> https://www.ibm.com/developerworks/mydeveloperworks/blogs/HermannSW/
>> ----------------------------------------------------------------------
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>>
>>
>>
>> From:   Andrew Welch <andrew.j.welch@xxxxxxxxx>
>> To:     xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>> Date:   07/05/2011 10:15 AM
>> Subject:        Re: [xsl] Java list extension
>>
>>
>>
>> > Now I need a way to discover the contents of a directory (files and
>> > other directorys). So far I have:
>>
>> You can get a list of all the files in the directory and
>> subdirectories by doing:
>>
>> <xsl:for-each
>>
select="collection('file:///path/to/dir/?select=*;recurse=yes;on-error=ignore
')">
>>  <xsl:value-of select="document-uri(.)"/>
>>
>>
>> --
>> Andrew Welch
>> http://andrewjwelch.com