Re: [xsl] xslt document function - recursive folder processing.

[Lighton Phiri <lighton.phiri@xxxxxxxxx>]

Hi Abel, thank you very much.

Question#1: How can I keep track of the folder attribute in the parent
template
(a). If I get what you mean, then this would effectively only work
with the parent nodes accessing child parameters; what I want to do
however is to access parent attributes in child nodes.
(b). If that is possible, do you suppose it would be feasible to use
this approach for a 3/4-level hierarchy of folders?

Question# 2:
What I meant to say in question 2 is: Is it possible to use the
file://D| syntax with relative path names? It seems not to work and I
was thinking that perhaps I could have been doing something wrong; my
implementation requires the use of relative pathnames --for now.


On 6 August 2011 14:34, Abel Braaksma <abel.online@xxxxxxxxx> wrote:
>> This is my first post;
>
> Welcome!
>
>> How can I keep track of the folder attribute in the parent template
>
> You're challenge is that you start from a new document node, from that
point
> on, the original document node is out of scope. However,
xsl:apply-templates
> can have a child, xsl:with-param. Use <xsl:with-param name="filename"
> select="@name" /> and inside the matching template, add <xsl:param
> name="filename" />. You can then refer to this by using the variable
> $filename.
>
>> The potion of code below fails until I explictly provide the absolute
>> path and also prepend it with file://D|
>
> Not sure what the question is for Q #2, but your conclusion is correct. You
> need to provide a URI. The exact syntax for a file-uri is often debated and
> can be processor dependent (i.e., some may require file:///, as after
> file:// for protocol, you must first provide the root /).
>
>> Is it possible for me to determine using XSLT the directory path of
>> the XML file being processed?
>
> Certain processors may provide extension functions for that. In XSLT 2.0,
> you can use the base-uri() function to find the filename (not quite: to
find
> the base uri) of a document. You can even use base-uri(documen('')) to get
> the filename of the executing XSLT file. If you need to stick to XSLT 1.0,
> you can pass the filename as a parameter on the commandline. Define the
> parameter as xsl:param in the root of your styleseet. Same solution works
> for getting the absolute current path (you Q #2).
>
> Cheers,
> Abel
>
>
>
>
>
> ------------------------------------------------------------------------
> From:   Lighton Phiri <lighton.phiri@xxxxxxxxx>
> Sent:   Saturday, August 06, 2011 12:34:26 PM
> To:     xsl-list
> Cc:
> Subject:        [xsl] xslt document function - recursive folder processing.
>
>
>
>> I am working with XSLT version 1.0 using xsltproc.
>>
>> This is my first post; please bare with me if I've missed out on any
>> of the house rules. I have tried as much as possible to replicate what
>> I am trying to do below. My senario is as follows:
>>
>> Folder Structure
>>
>> folder/
>> |-- index.xml
>> |-- dir1
>> |   |-- d1f1.xml
>> |   |-- d1f2.xml
>> |   |--
>> |-- dir2
>> |   |-- d2f1.xml
>> |   |-- d2f2.xml
>> |   |--
>>
>>
>> Current XSLT stylesheet
>>
>>  <?xml version="1.0" encoding="utf-8"?>
>>
>>    <xsl:stylesheet version="1.0"
>>    xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>>
>>      <xsl:output method="xml" indent="yes" encoding="utf-8" />
>>
>>      <xsl:template match="folder">
>>        <xsl:apply-templates select="document(file)/file" />
>>      </xsl:template>
>>
>>      <xsl:template match="file">
>>        <name>
>>      <xsl:value-of select="name" />
>>        </name>
>>        <link>
>>      <file>document(../dir2/d2f1.xml, /)/file/name</file>
>>      <description>document(../dir2/d2f1.xml,
>> /)/file/description</description>
>>        </link>
>>      </xsl:template>
>>
>>    </xsl:stylesheet>
>>
>>
>> index.xml file
>>
>> <?xml version="1.0" encoding="utf-8"?>
>> <folder name="dir1">
>>   <file>f1.xml</file>
>>   <file>f2.xml</file>
>> </folder>
>>
>>
>> d1f1.xml
>>
>> <?xml version="1.0" encoding="utf-8"?>
>> <file>
>>   <name>File 1</name>
>>   <description>I am file 1</description>
>>   <link>dir2/d2f1.xml</link>
>> </file>
>>
>> d2f2.xml
>>
>> <?xml version="1.0" encoding="utf-8"?>
>> <file>
>>   <name>File 2</name>
>>   <description>I am file 2</description>
>> </file>
>>
>>
>> Question# 1:
>> How can I keep track of the folder attribute in the parent template so
>> I can make use of it when calling the child templates?
>>
>> Question# 2:
>>
>> The potion of code below fails until I explictly provide the absolute
>> path and also prepend it with file://D|
>>
>> this fails
>>        <link>
>>      <file>document(../dir2/d2f1.xml, /)/file/name</file>
>>      <description>document(../dir2/d2f1.xml,
>> /)/file/description</description>
>>        </link>
>>
>> this works (I stole this idea from
>> http://www.dpawson.co.uk/xsl/sect2/N2602.html#d3862e403)
>>
>>        <link>
>>      <file>document(file://D|/home/phiri/dir2/d2f1.xml)/file/name</file>
>>
>>
 <description>document(file://D|/home/phiri/dir2/d2f1.xml)/file/description</
description>
>>        </link>
>>
>> Question# 3:
>> Is it possible for me to determine using XSLT the directory path of
>> the XML file being processed?
>> All sources I have found online seem to suggest its not possible to
>> evaluate the directory path of the XML file being processed.
>
>



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------------------------------
Lighton Phiri
http://lightonphiri.org/
------------------------------