Re: [xsl] Stripping payloads

[Mohit Anchlia <mohitanchlia@xxxxxxxxx>]

Sorry I didn't specify it correctly. I need to extract just the
payload value. So output would like something like:

output 1 (no payload value):
 <api>
    <name>get</name>
    <payload></payload>
 </api>

output 2 (just the payload value):

assaddddd

On Mon, Aug 22, 2011 at 1:15 PM, Mohit Anchlia <mohitanchlia@xxxxxxxxx>
wrote:
> On Sun, Aug 21, 2011 at 10:46 AM, Martin Honnen <Martin.Honnen@xxxxxx>
wrote:
>> Mohit Anchlia wrote:
>>>
>>> I have payload something like
>>>
>>> <api>
>>>    <name>get</name>
>>>    <payload>assaddddd</payload>
>>> </api>
>>>
>>> We have got a requiement to save all incoming request except the
>>> "payload" on the wire. Also, one of the option I think is to use XSL
>>> transformation to strip the payloads. I need some suggestion on if
>>> it's the good way and also how can I possibly do it using xslt.
>>
>> Well if you want to strip the payload element(s) then do
>>
>> <xsl:template match="@* | node()">
>>  <xsl:copy>
>>    <xsl:apply-templates select="@* | node()"/>
>>  </xsl:copy>
>> </xsl:template>
>>
>> <xsl:template match="payload"/>
>
> In the same transformation is it possible to output 2 separate pieces:
>
> 1) Payload
> 2) Everything but payload
>
> We need to persist them but separately
>
>>
>>
>>
>>
>> --
>>
>>        Martin Honnen --- MVP Data Platform Development
>>        http://msmvps.com/blogs/martin_honnen/