Re: [xsl] anyURI problem

[Andrew Welch <andrew.j.welch@xxxxxxxxx>]

On 26 August 2011 09:33, Jan Pour <xpouj04@xxxxxxxxx> wrote:
> Hi,
>
> I tried both ways of how to cope with [Content_Types].xml
> file in xsl:result-document href attribute:
>
>> Try using the iri-to-uri() function to turn this into a valid URI.
>>
>> Saxon is fussier than some other products about insisting that URIs are
>> valid.
>>
>> Michael Kay
>> Saxonica
>
>> That didnt work for me, but
>> href="{encode-for-uri('[Content_Types].xml')}"
>> did.
>>
>> Or verbose
>> href="%5bContent_Types%5d.xml"
>>
>> Gerrit
>
> in Saxon 8 I was able to generate such file, but with versions 9.*
> I was not successful. With encode-for-uri() function 0-length file was
> generated with following error message:
>
> java.net.URISyntaxException: Illegal character in path at index 21:
> file:///C:/xslt/test/[Content_Types].xml
>
> I tried Saxon versions: 9, 9.1 and 9.3he
> Is there any other solution?

If you don't post the code it's hard to see where you are going wrong....

Guessing, you've probably wrapped the whole path in encode-for-uri,
rather than just the filename:

href="{concat('file:///C:/xslt/test/',
encode-for-uri('[Content_Types.xml'))}"



--
Andrew Welch
http://andrewjwelch.com