Re: [xsl] Can a single XPath statement duplicate the functionality of this verbose <xsl:choose> statement?

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

Mark,

Try this:

  for $n in  .
    return
      string((../Location/@*[name() = name($n/@*[1])],
../Location/@denomination, 0)[1])


On Sun, Oct 23, 2011 at 6:06 PM, Mark <mark@xxxxxxxxxxxx> wrote:
> <Stamp>
> B  B  B <Formats souvenir-sheet="2896"/>
> B  B  <Location denomination="5"/>
> B  B  <Location souvenir-sheet="1"/>
> B  </Stamp>
>



--
Cheers,
Dimitre Novatchev
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