Subject: Re: [xsl] Can a single XPath statement duplicate the functionality of this verbose <xsl:choose> statement? From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Sun, 23 Oct 2011 18:50:53 -0700 |
Mark, Try this: for $n in . return string((../Location/@*[name() = name($n/@*[1])], ../Location/@denomination, 0)[1]) On Sun, Oct 23, 2011 at 6:06 PM, Mark <mark@xxxxxxxxxxxx> wrote: > <Stamp> > B B B <Formats souvenir-sheet="2896"/> > B B <Location denomination="5"/> > B B <Location souvenir-sheet="1"/> > B </Stamp> > -- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- Never fight an inanimate object ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play ------------------------------------- Facts do not cease to exist because they are ignored. ------------------------------------- I finally figured out the only reason to be alive is to enjoy it.
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