Re: [xsl] Using "except" where some nodes are copies (not the original)?

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

Perhaps:

(A, B, C)
        [for $n in .
           return
              not( ($B, C)
                         [deep-equal(., $n)]
                    )
         ]




On Wed, Dec 28, 2011 at 3:17 PM, Costello, Roger L. <costello@xxxxxxxxx>
wrote:
> Hi Folks,
>
> How do I do set subtraction where some of the nodes in the two sets may be
copies (not originals)?
>
> Please allow me to explain.
>
> Consider this XML document:
>
> <Test>
> B  B <A/>
> B  B <B/>
> B  B <C/>
> </Test>
>
> Set <Test> as the context node.
>
> This operation:
>
> B  B (A, B,, C) except (B, C)
>
> returns:
>
> B  B (A)
>
> Nice.
>
> Now, make a copy of B and store it into a variable:
>
> B  B  B <xsl:variable name="B" as="element(B)">
> B  B  B  B  B  B  B  B <xsl:copy-of select="B" />
> B  B  B  </xsl:variable>
>
> Run the same operation, but using the variable:
>
> B  B (A, B, C) except ($B, C)
>
> Returns:
>
> B  B (A, B)
>
> Ouch!
>
> B I don't want that behavior. I want:
>
> B  B (A, B, C) except ($B, C)
>
> to return:
>
> B  B (A)
>
> How do I achieve the behavior I desire?
>
> That is, how do I do set subtraction where some of the nodes in the two sets
may be copies?
>
> /Roger
>



--
Cheers,
Dimitre Novatchev
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