Re: [xsl] Path according to a child node attribute

[Martin Honnen <Martin.Honnen@xxxxxx>]

Gian Paolo Bernardini wrote:

> 	<Class code="B">
> 		<SubClass code="b1"/>
> 		<SubClass code="b2"/>
> 		<Rubric kind="preferred">
> 			<Label xml:lang="it">FUNZIONI CORPOREE</Label>
> 			<Label xml:lang="en">BODY FUNCTIONS</Label>
> 		</Rubric>
> 		<Rubric kind="definition">
> 			<Label xml:lang="it">Le funzioni corporee sono
> ..</Label>
> 			<Label xml:lang="en">Body functions ...</Label>
> 		</Rubric>
> 	</Class>

> The aim is the same, now it must be chosen the text inside the<Label
> xml:lang="it">  inside<Rubric kind="preferred">  since there are more kind
> attributes for<Rubric>  element.

>     <xsl:template match="Class" mode="path">
>       <xsl:variable name="next" select="key('k1', SuperClass/@code)"/>
>       <xsl:if test="$next">
>         <xsl:apply-templates select="$next" mode="path"/>
>         <xsl:text>/</xsl:text>
>       </xsl:if>
>       <xsl:value-of select="concat(@code,' ', Rubric)"/>
>     </xsl:template>

You just need to change the
  <xsl:value-of select="concat(@code,' ', Rubric)"/>
to
  <xsl:value-of select="concat(@code,' ', Rubric[@kind = 
'preferred']/Label[lang('it')])"/>


--

	Martin Honnen --- MVP Data Platform Development
	http://msmvps.com/blogs/martin_honnen/