Re: [xsl] what's the best way to do this

[Peder <peet.sdu@xxxxxxxxx>]

Hi Roelof,

You can do something like this:

<xsl:variable name="maanden" select="'januari', 'februari', 'maart', 'april',
'mei', 'juni', 'juli', 'augustus', 'september', 'oktober', 'november',
'december'"/>

And in your template for month:
<xsl:template match="month">
	<a href="#"><xsl:value-of select="index-of('maanden', number(@value))"/></a>
</xsl:template>

Regards,

Peter

On Jan 5, 2012, at 11:33 , Roelof Wobben wrote:

>
>
> Hello,
>
>
>
> Last question and then I have the site ready.
>
>
>
> I have now this xml :
>
>
>
> <menu>
>
>     <section id="9" handle="dagboek">Dagboek</section>
>
>           <year value="2005">
>
>           <month value="03">
>
>               <entry id="17" />
>
>           </month>
>
>            <month value="02">
>
>                <entry id="16" />
>
>                <entry id="15" />
>
>                <entry id="14" />
>
>            </month>
>
>          </year>
>
> </menu>
>
>
>
> And I like to have this output :
>
>
>
> <div id="firstpane" class="menu_list">
>
>     <p class="menu_head">2005</p>
>
>     <div class="menu_body">
>
>         <a href="#">februari</a>
>
>         <a href="#">maart </a>
>
>     </div>
>
> </div>
>
>
>
> And I wonder now what's the best approach to get all the months under the
year ?
>
>
>
> Regards,
>
>
>
> Roelof