[xsl] How to compare two (possibly dissimilar) XML's (XSLT1.0)

[Mark Anderson <mark@xxxxxxxxxxxxxxxxxxxxxxxx>]

Hi Guys

I have an XML comparison XSL that works well for identical XML's; however, I
need to create a version that will compare two slightly dissimilar XML's
(whose structure I do not know--other than root element's name).

One will always be a superset of the other (if different).

For example

A contains

<elements>
    <element1>
        <element1a>1a</element1a>
        <element1b>1b</element1b>
        <element1c>1c</element1c>
    </element1>
    <element2>
        <element2a>2a</element2a>
        <element2b>2b</element2b>
        <element2c>2c</element2c>
    </element2>
    <element3>
        <element3a>3a</element3a>
        <element3b>3b</element3b>
        <element3c>3c</element3c>
    </element3>
</elements>


B Contains

<elements>
    <element1>
        <element1a>1a</element1a>
        <element1b>1b</element1b>
        <element1c>1c</element1c>
    </element1>
    <element3>
        <element3a>4a</element3a>
        <element3c>4c</element3c>
    </element3>
</elements>

I want to iterate through every element and attribute in A, find the
corresponding element in B (if it exists) and compare their values.

For example, the output needs to indicate the following:

element2 is missing
element2/element2a is missing
element2/element2b is missing
element2/element2c is missing
element3/element3b is missing
element3a's value is different
element3b's value is different

Any help greatly appreciated

Regards

Mark