Re: [xsl] how to achieve this ?

[Michel Hendriksen <michel.hendriksen@xxxxx>]

Sounds like HTML/javascript problem, is another list.

On 1/23/12, Roelof Wobben <rwobben@xxxxxxxxxxx> wrote:
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> Thanks,
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> It solved the id problem but the menu still don't work right.
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> It still don't work as as accordian menu. See http://test.tamarawobben.nl
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> Roelof
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> ---------------------------------------- > From: bbosgoed@xxxxxxx > Date:
> Mon, 23 Jan 2012 08:35:36 +0100 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx >
> Subject: Re: [xsl] how to achieve this ? > > > Op 23 jan 2012, om 08:26
> heeft Roelof Wobben het volgende geschreven: > > Not knowing how the input
> looks like, i would say that: > <ul class="menu" id={concat('menu',
> @value)}> > > should do it for you, its a short notation for xsl:value-of
> select > > > > For a menu I have to take care that every <menu class> get a
> unique id. > > > > I thought this would work : > > > > <xsl:template
> match="year"> > > <ul class="menu" id= "concat ('menu', @value)" > > > <li>
>> > <a href="#"> <xsl:value-of select="@value"/> </a> > > <ul
> class="acitem"> > > <xsl:apply-templates select="month" /> > > </ul> > >
> </li> > > </ul> > > </xsl:template> > > > > But it don't work. > > > > Do I
> have to use here <xsl:value-of> or is there a better way ? > > >