Re: [xsl] Get the first Array element

[henry human <henry_human@xxxxxxxx>]

If I have it in this way in the otherwise part I get for that Taxtotal which
HAS NO Amount still a result 
(<amount>00000000000000</amount>)
Therfore I did
:
  <xsl:otherwise></xsl:otherwise>
The solution works fine for me, thnak you
guys!
But I think still this statement : <xsl:when
test="cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount 

does not query ONLY the
taxtotal elemnets which HAS AN amount but the other taxtotals too?
Kind regards
hny

----- Urspr|ngliche Message -----
Von: Michel Hendriksen
<michel.hendriksen@xxxxx>
An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
CC: 
Gesendet:
12:27 Freitag, 11.Mai 2012
Betreff: Re: [xsl] Get the first Array element
First test had a space it seems, so never matched

So something like: (second
part not needed I guess, test might better)
<xsl:choose>
    <xsl:when
test="cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount &gt;= 0">
   
<xsl:value-of
select="format-number(floor(cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount),'+
0000000000000;-0000000000000')
"/>
    </xsl:when>

    <xsl:when
test="cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount &lt; 0">
    <xsl:value-of
select="format-number(floor(cac:TaxTotal[child::cbc:Amount][1]/cbc:Amount),'+
0000000000000;-0000000000000')
"/>
    </xsl:when>

 
<xsl:otherwise>00000000000000</xsl:otherwise>
</xsl:choose>