|
Subject: [xsl] How to give an attribute a QName value, with the appropriate prefix? From: "Costello, Roger L." <costello@xxxxxxxxx> Date: Mon, 27 Aug 2012 20:37:29 +0000 |
Hi Folks,
I want to transform this:
<xs:attribute name="test" />
to this:
<xs:attribute name="test" type="xs:anySimpleType" />
Here is the code that I tried:
<xsl:template match="xs:attribute">
<xsl:copy>
<xsl:copy-of select="@*" />
<xsl:attribute name="type"><xsl:value-of
select="QName('http://www.w3.org/2001/XMLSchema', 'anySimpleType')"
/></xsl:attribute>
<xsl:sequence select="node()" />
</xsl:copy>
</xsl:template>
Unfortunately that code produces this:
<xs:attribute name="test" type="anySimpleType" />
Notice that there is no prefix on anySimpleType.
What's the best way to accomplish my objective?
I want the prefix on anySimpleType to match the prefix on the <attribute>
element, whether it be xs: or xsd: or anything else.
/Roger
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| Re: [xsl] finding the position of a, Wolfhart Totschnig | Thread | Re: [xsl] How to give an attribute , G. Ken Holman |
| Re: [xsl] finding the position of a, Wolfhart Totschnig | Date | Re: [xsl] How to give an attribute , G. Ken Holman |
| Month |