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Subject: Re: [xsl] Walking a xsl:key From: "Tony Graham" <tgraham@xxxxxxxxxx> Date: Fri, 22 Feb 2013 13:15:34 -0000 (GMT) |
On Fri, February 22, 2013 10:58 am, Ihe Onwuka wrote:
> I thought I saw somewhere that if you omit the 2nd argument to the key
> function a set of all nodes in the named xsl:key will be returned.
> This is the behaviour I want, is it possible?
It doesn't work as you say. You can't omit the second argument, and if
you provide an empty sequence as the second argument, XSLT 2.0 [1] says:
If the second argument is an empty sequence, the result of the
function will be an empty sequence.
The current XSLT 3.0 WD [2] says you get either the empty sequence or "
the set of nodes having an empty sequence as the value of the key
specifier.", depending on the new xsl:key/@composite value (or its
absence).
You can get the effect you want by making a key where the @use value is
always the same, e.g., 'true()', so "key('my-key', true())" gets you all
the nodes matched by the xsl:key.
Regards,
Tony Graham tgraham@xxxxxxxxxx
Consultant http://www.mentea.net
Mentea 13 Kelly's Bay Beach, Skerries, Co. Dublin, Ireland
-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --
XML, XSL-FO and XSLT consulting, training and programming
[1] http://www.w3.org/TR/xslt20/#keys
[2] http://www.w3.org/TR/xslt-30/#func-key
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