Re: [xsl] format-number() issue

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2013-08-16 10:11 -0400, Nathan Tallman wrote:
> I'm trying to use format-number like this:
>
> <xsl:variable name="unitid" select="lower-case(/ead/archdesc/did/unitid)"/>
> <xsl:variable name="number" select="substring($unitid, 3)" />
> <xsl:value-of select="format-number($number, '0000')"/>
>
> I've seen many examples online of using a variable in the first spot
> with format-number, but I keep getting a validation error, "Required
> item type of first argument of format-number() is numeric; supplied
> value has item type xs:string."
>
> I've tried sticking as="xs:integer" in <xsl:variable  name="number">
> and adding the xs namespace, but then I get this error, "Required item
> type of value of variable $number is xs:integer; supplied value has
> item type xs:string".

It surprises me that that didn't work.

> I can't make $unitid an integer, as it has alpha
> characters in it (which I remove in $number).
>
> Can someone point out my errors or give me a hint?

You could cast the argument to an acceptable type:

  format-number( xs:integer($number), '0000' )

... or if you aren't dealing with integers:

  format-number( xs:double($number), '0000' )

I hope this helps.

. . . . . . . . Ken


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