Subject: [xsl] Replacing \U+00A0 From: Mario Madunic <mario.madunic@xxxxxxxxxxxx> Date: Fri, 23 Aug 2013 12:25:01 -0700 |
Hi, Having a problem replacing the following string in some XML, \U+00A0. It is appearing as is in the XML. Example: <p>This para\U+00A0contains.</p> Using Saxon HE 9.5.0.1J. Tried the following: <xsl:value-of select="if (contains(., '\U+00A0')) then replace(., '\U+00A0', ' ') else ." />. Am able to find the string in question (using contains()) but am unable to replace it. Any insight and help will be appreciated. Thanks Mario Madunic | Software Developer | AeroInfo Systems, A Boeing Company | mario.madunic@xxxxxxxxxxxx | #200-13575 Commerce Parkway | Richmond, BC, V6V 2L1, Canada | www.aeroinfo.com | www.boeing.com
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] XSL-FO: Repeated table co, Mario Madunic | Thread | Re: [xsl] Replacing \U+00A0, Martin Holmes |
RE: [xsl] XSL-FO: Repeated table co, Mario Madunic | Date | Re: [xsl] Replacing \U+00A0, Martin Holmes |
Month |