Subject: Re: [xsl] Duplicate Elimination|
From: David Carlisle <davidc@xxxxxxxxx>
Date: Thu, 13 Mar 2014 11:56:39 +0000
By all means reply but from an educational perspective point out that your preference for for-each-group, has no set-theoretic interpretation,
It's iterating through representatives of the quotient set if you factor by the relation implied by the group-by clause.
will not work for anybody restricted to XSLT 1.0
It's easy to rewrite any such use of for-each-group as xsl-for-each plus a filter using a key (look up muenchian grouping for the details)
and does not port to XPATH or XQuery.
For xquery you can use the similar group-by clause so long as you are using V3 http://www.w3.org/TR/xquery-30/#id-group-by
________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.