Re: [xsl] How to show explicitly the implicit sequence constructor?

Subject: Re: [xsl] How to show explicitly the implicit sequence constructor?
From: David Carlisle <davidc@xxxxxxxxx>
Date: Sat, 29 Mar 2014 10:38:22 +0000
On 29/03/2014 09:28, Costello, Roger L. wrote:
Hi Folks,

In the following template rule is an implicit sequence constructor. The sequence constructor expresses this: "Show the value of Title, then show the value of Author."

     <xsl:template match="Book">
         <xsl:value-of select="Title" />
         <xsl:value-of select="Author" />
     </xsl:template>

Is there a way to explicitly show the sequence constructor?

For example, this would be a neat way to explicitly show the sequence constructor:

     <xsl:template match="Book">
         <xsl:sequence>
             <xsl:value-of select="Title" />
             <xsl:value-of select="Author" />
         </xsl:sequence>
     </xsl:template>

Unfortunately that is not legal.

Is there a way to explicitly show the sequence constructor?

/Roger


you could use


<xsl:sequence select="string(Title),string(Author)" separator=""/>

although that's a sequence of strings not a sequence of text nodes, it possibly comes to the same thing in the end.

David



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