Subject: Re: [xsl] Can the default function namespace be undeclared in XSLT? From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sun, 1 Jun 2014 23:03:20 -0000 |
On 1 Jun 2014, at 23:23, Dimitre Novatchev dnovatchev@xxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > On Sun, Jun 1, 2014 at 3:06 PM, Michael Kay mike@xxxxxxxxxxxx > <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: >> In XSLT the default function namespace is always the "fn" namespace; this cannot be changed. > > Thank you. > > Is it correct to conclude that due to this, an instance of a > user-defined type that is in no-namespace can only be constructed > using casting, but not using the name of the type as a constructor > function? > In 3.0 you can also use Q{}mytype(...) Michael Kay Saxonica
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