Subject: Re: [xsl] Special characters in regex expression From: "Michael Dykman mdykman@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 23 Jul 2014 20:21:15 -0000 |
It is my understanding that Java' regular expression builtin emulates 'pcre' pretty closely. To escape spacial characters that have special meaning in a regular expression, defining it as a character class (using the square bracket notation) generally works ie. if you want to match a question mark at the beginning of a line, use: "^[?].*$" On Wed, Jul 23, 2014 at 3:55 PM, mike@xxxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > Exclamation mark is not a special character in XPath regular expressions, > and there does not need to be (and must not be) escaped. > > Negative lookaheads are not supported in the XPath regular expression > dialect. > > You can't assume that all regular expression dialects are the same. > > Michael Kay > > Saxonica > > > >> Dear All, >> >> I am using xsl:analyze-string to retrieve and replace punctuation, >> however, I got the following error: >> >> Error in regular expression: net.sf.saxon.trans.XPathException: Syntax >> error at char 6 in regular expression: Escape character '!' not allowed. >> >> How should I escape and match '?' and '!' ? I am also using a negative >> look-ahead, why isn't that working? >> >> Here is a sample from my code, thanks, >> >> Gabor >> >> >> <xsl:template match="//TEI:p//text()[ not >> ((parent::TEI:note)|(parent::TEI:hi)|(parent::TEI:date))]"> >> <xsl:analyze-string select="." regex="(\.|\!|\?)(?!\)|\.|\d|\w)"> >> >> <xsl:matching-substring> >> >> <xsl:element name="seg" >> namespace="http://www.tei-c.org/ns/1.0"><xsl:value-of >> select="."/></xsl:element> >> </xsl:matching-substring> >> <xsl:non-matching-substring> >> <xsl:value-of select="."/> >> </xsl:non-matching-substring> >> </xsl:analyze-string> >> > > XSL-List info and archive > EasyUnsubscribe (by email) -- - michael dykman - mdykman@xxxxxxxxx May the Source be with you.
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