Re: [xsl] Replacing an apostrophe in a string

["Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

As I have shown in my answer, tricks with swapping quotes and apostrophes
are no longer necessary.

In XPath 2.0 and up one can code ' or " by simply doubling it.


On Thu, Sep 4, 2014 at 11:58 AM, Craig Sampson craig.sampson@xxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

>  Sorry for the noise. I got it working right after posting for help.
>
>  The solution was to swap the quotes around in the statement, which I
> thought Ibd already tried, but it worked this time.
>
>
>
> Eg:
>
>
>
> <xsl:variable name=bnewStringb select=breplace($oldString,
b&apos;b ,
> bXXXb)b/>
>
>
>
> Thanks,
>
>   Craig
>    XSL-List info and archive <http://www.mulberrytech.com/xsl/xsl-list>
> EasyUnsubscribe <-list/782854> (by
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>



--
Cheers,
Dimitre Novatchev
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