Re: [xsl] From flat to hierarchical structure

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

nick public nickpubl@xxxxxxxxx wrote:

> I need to convert a flat structure like this
>
> <root>
>     <H>1</H>
>     <I>1-1</I>
>     <I>1-2</I>
>     <I>1-3</I>
>     <H>2</H>
>     <I>2-1</I>
>     <I>2-2</I>
>   </root>
>
> in one like this
>
> <root>
>     <H>
>        1
>        <I>1-1</I>
>        <I>1-2</I>
>        <I>1-3</I>
>     </H>
>     <H>
>        2
>        <I>2-1</I>
>        <I>2-2</I>
>     </H>
> </root>

Can't you use XSLT 2.0 with

  <xsl:template match="root">
    <xsl:copy>
      <xsl:for-each-group select="*" group-starting-with="H">
        <xsl:copy>
          <xsl:apply-templates select="node(), current-group() except ."/>

? That way it is easy to process your input.

With XSLT 1.0 you might want to define a key

<xsl:key name="group" match="I" use="generate-id(preceding-sibling::H[1])"/>

and then you can use

<xsl:template match="root">
  <xsl:copy>
    <xsl:apply-templates select="H"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="H">
  <xsl:copy>
    <xsl:apply-templates select="node() | key('group', generate-id())"/>
  </xsl:copy>
</xsl:template>

Both approaches need the identity transformation template to copy the 
remaining nodes like the I elements.