Subject: Re: [xsl] How do I properly define a unix saxon script command line From: "Wolfgang Laun wolfgang.laun@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 12 Nov 2014 11:00:55 -0000 |
What I use for invoking Saxon is similar to this: #! /bin/sh # Make sure we have at least one parameter: the XML input document # Additional arguments will be passed to Saxon. case $# in 0) echo "no pathname for xml input file" exit;; esac xml=$1 shift # Set JAVA_HOME (to make it stand out) and define path to java. JAVA_HOME=/extra/JDK8u20/jdk1.8.0_20 java=$JAVA_HOME/bin/java # Set Saxon jar (to make it stand out) SAXON_JAR=/extra/saxon/saxon9he.jar # Set stylesheet pathname (to make it stand out) XML2CSV_XSL=/home/cwilbur/stylesheets/xml2csv.xsl # Call transformation using the shell variables set before # and pass additional parameters. $java -cp $SAXON_JAR net.sf.saxon.Transform \ -xsl:$XML2CSV_XSL -s:$xml "$@" # end of script You store this on a file /home/cwilbur/bin/xml2csv Make sure to $ chmod ugo+x /home/cwilbur/bin/xml2csv and then you (and everybody else on this system) can invoke this using ~cwilbur/bin/xml2csv todays.xml The variables commented "to make it stand out" need to be adapted to your system. Also, I'm using cwilbur as your user name, which is just a guess. Finally, your ~cwilbur/bin may not be the best place for a shell script to be used by everybody on this system, HTH Wolfgang On 11 November 2014 22:47, Catherine Wilbur cwilbur@xxxxxxxxxxx < xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > Want to write a command line to call Saxon processor from a unix script > line. Am using Saxon-HE from Unix command line to convert my XML file into > a CSV file so it can be uploaded into a DB Table. We are using the DB table > as input into our AP interface in ERP E1. Had to switch to Saxon processor > because xsltproc does not work with xsl 2.0. > > In the command line call I need to specify two classpaths (Classpath for > JAVA, Classpath for SAXON jar files) > > How would I call the saxon processor in a unix script and pass it the > following information > JavaClassPath, SaxonJarClassPath, InputFile, StylesheetFile, OutputFile > > So far this is the unix command line I came across on the web. Read thru > page 853-854 of XSLT 2.0 3rd Edition Programmer's Reference and it does not > quite give me what I am looking for. Where would I find all the Saxon > command line options > Want to do saxon conversion of XML file within a unix shell script. We > have Java on Unix box. Loaded Saxon jar files in a different directory on > unix box. Loaded stylesheet on unix box. Loaded InputFile on unix box. > > *saxon -r saxonjarclasspath/saxon.jar -m javaclasspath -s:Input_File > -xsl:Stylesheet_File -o Output_File* > > _____________________________________________________________________ > Catherine Wilbur | Senior Application Programmer | IT Services > 401 Sunset Avenue, Windsor ON Canada N9B 3P4 > (T) 519.253.3000 Ext. 2745 | (F) 519.973.7083 | (E) > cwilbur@xxxxxxxxxxx > www.uwindsor.ca/its > XSL-List info and archive <http://www.mulberrytech.com/xsl/xsl-list> > EasyUnsubscribe <-list/528976> (by > email <>)
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