Subject: Re: [xsl] Muenchian work if more than one value is present From: "Liam R. E. Quin liam@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 20 Mar 2015 19:13:45 -0000 |
On Fri, 2015-03-20 at 12:56 +0000, Russell Urquhart russurquhart1@xxxxxxxxxxx wrote: > As for moving towards XSLT 2.0, i have been wanting to get there but > feel i first have to fully understand XSLT 1.0 first! But i'm > getting there! "I can't move to these new-fangled automobiles until I understand how to make my own cartwheel with a spokeshave!" :-) Seriously, I'd say, build some tests and try moving as soon as you can. Liam > > Thanks to everyone here for your time and patience! > > > Russ > > > > On Thu, Mar 19, 2015 at 07:34:23PM +0000, Wendell Piez > wapiez@xxxxxxxxxxxxxxxxxxxx: > > Russ, > > > > Yeah -- the for-each pulls all the errata_section elements that > > happen to be the first one of the entire set with the same value > > for module_impacted -- except that since you've added > > module_impact siblings, it will be those that are the first one of > > the set of all errata_section with *any* of the same > > module_impacted values. The key can work many-to-one, and it does. > > This means in principle a module_impacted can be dropped (if it > > never appears outside parents that are also bound to other modules > > mentioned earlier). > > > > To use Muenchian grouping, write your key to the module_impacted > > elements themselves (by their values), not their parents. Then > > > > for-each select="//module_impacted[generate-id() = > > generate-id(key('module_impact_mentions',string(.))[1])]"> > > > > to iterate over these values (or rather, over a set of node > > proxies for them). > > > > Or ditch the Muenchian grouping and join the modern world - XSLT > > 2.0. > > > > Cheers, Wendell > > > > > > On Wed, Mar 18, 2015 at 12:45 PM, russurquhart1@xxxxxxxxxxx< > > xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > > > > > Hi All, > > > > > > I have a question about using Muenchian Method in a specific > > > situation. > > > > > > I have an xml source file like the following: > > > > > > <errata_section id="i875" > > > errata_type="bug"><title>Title</title><description> <para> > > > Following a warm Reset </para></description><devices_impacted> > > > <device_name>VAZER</device_name></devices_impacted><module_impacted>Boot</module_impacted></errata_section> > > > > > > > > > The existing xsl, that i am supporting, but didn't write, uses > > > the following key: > > > > > > <xsl:key name="module-index" match="errata_section" > > > use="module_impacted"/> > > > > > > And they have used the following Muenchian Method algorithm to > > > go through all the unique module_impacted elements. > > > > > > > > > <xsl:for-each select="//errata_section[generate-id(.)=generate- > > > id(key('module-index', module_impacted)[1])]"> <xsl:sort > > > select="module_impacted"/> > > > <!-- Determine module_impacted elements, for given device_name, > > > and output table. --> > > > > > > </xsl:for-each> > > > > > > Everything went fine until, over time, we have added additional > > > module_impacted siblings to the errata_section element like this: > > > > > > <errata_section id="i876" > > > errata_type="bug"><title>Title</title><description> <para> > > > Following a warm Reset </para></description><devices_impacted> > > > <device_name>VAZER</device_name></devices_impacted><module_impacted>Boot</module_impacted><module_impacted>Power- > > > On</module_impacted><module_impacted>DMA</module_impacted></errata_section> > > > > > > > > > Once this happened we started to see that not all > > > module_impacted elements were being found for the given > > > device_name. My question is, is this happening because the > > > element we are doing the generate-id function on, in some cases > > > would have multiple siblings in a given errata_section element? > > > Most of the examples i have seen of using Muenchian Method are > > > keying on a unique elment value that doesn't have any similar > > > named siblings. > > > > > > I'm just trying to understand if this structure would work at > > > all. Thanks for any info you can provide and thank you Martin > > > Honnen for your help so far! > > > > > > Russ
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