Subject: [xsl] Get children and text, excluding a child From: "Rick Quatro rick@xxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 12 Jun 2015 20:44:15 -0000 |
Hello, Here is my input xml: <?xml version="1.0"?> <root> <span><number>9.3</number> <code>protected</code> members</span> <span><number>9.4</number> miscellaneous members.</span> </root> Here is the desired output: <?xml version="1.0"?> <root> <span> <code>protected</code> members</span> <span> miscellaneous members.</span> </root> I want to output all of the elements and text of the original <span> element, but without the <number> element. I am using this for my xsl: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0"> <xsl:output method="xml" indent="yes"/> <xsl:template match="/root"> <root> <xsl:for-each select="span"> <xsl:copy-of select="descendant::*[not(self::number)]"/> </xsl:for-each> </root> </xsl:template> </xsl:stylesheet> This is my current (incorrect) output: <?xml version="1.0" encoding="UTF-8"?> <root> <code>protected</code> </root> Any help or pointers would be appreciated. Thanks. Rick Quatro Carmen Publishing Inc. 585-366-4017 rick@xxxxxxxxxxxxxxx
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