Subject: Re: [xsl] XPATH 1.0: Selecting an element attribute starting from a self:: attribute From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 17 Jun 2015 14:05:06 -0000 |
<library>
<catalog>
<book id="_1" name="Book1"/>
<book id="_2" name="Book2"/>
<book id="_3" name="Book3"/>
</catalog>
<customer>
<borrowed bookId="_1"/>
<borrowed bookId="_2"/>
</customer>
</library>
In an appplication (Windows WPF / XAML), my execution context is e.g. the element "borrowed" (e.g. <borrowed bookId="_1"/>).
I have to find the name of the book which is referenced as bookId.
So my XPATH expression is like:
"//book[@id=self::*/@bookId]/@name"
Read as: give all books whose id equals to the bookId of the current node.
The context node inside of the predicate [@id = self::*/@bookId] is the "book" element so both @id as well as self::* are evaluated with the "book" element as the context node and self::* simply selects that "book" element.
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